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<record version="1" id="105">
 <title>loop example of Biot-Savart law</title>
 <name>LoopExampleOfBiotSavartLaw</name>
 <created>2006-01-14 21:45:06</created>
 <modified>2006-01-14 21:45:06</modified>
 <type>Example</type>
<parent id="104">quarter loop example of Biot-Savart law</parent>
 <creator id="1" name="bloftin"/>
 <modifier id="1" name="bloftin"/>
 <author id="1" name="bloftin"/>
 <classification>
	<category scheme="msc" code="41.20.Gz"/>
 </classification>
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 <content>Here we will examine two examples of the Biot-Savart law, one simple and the other more challenging.  To begin we will find the magnetic field at the center of a current carrying loop as shown in figure 1

\begin{figure}
\includegraphics[scale=.8]{CurrentLoop.eps}
\vspace{10 pt}
\caption{Figure 1: Current Loop}
\end{figure}

this setup is the same as the quater loop example of Biot-Savart law where  we have

$$ d{\bf l} \times \hat{{\bf r}} = dl \, sin(\pi/2) $$
$$dl = r d\theta$$

giving us a similar integral, except from 0 to 2 $\pi$ and the lack of a minus sign since the current is going in the opposite direction so the magnetic field will be out of the web browser

$$ {\bf B} = \hat{{\bf k}} \frac{\mu_0 I}{4 \pi r} \int_0^{2\pi} \, d \theta $$

taking the integral gives the magnetic field at the center of the loop

$$ {\bf B} = \frac{\mu_0 I \hat{{\bf k}}}{2 \pi r} $$</content>
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