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<record version="2" id="189">
 <title>frictionless inclined plane</title>
 <name>FrictionlessInclinedPlane</name>
 <created>2006-06-18 21:44:19</created>
 <modified>2006-06-18 22:43:10</modified>
 <type>Example</type>
<parent id="186">Newton's laws of motion</parent>
 <creator id="1" name="bloftin"/>
 <modifier id="1" name="bloftin"/>
 <author id="1" name="bloftin"/>
 <classification>
	<category scheme="msc" code="45.50.Dd"/>
	<category scheme="msc" code="45.50.Pk"/>
	<category scheme="msc" code="45.50.-j"/>
 </classification>
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 <content>The inclined plane is a common example of Newton's laws of motion.  It was used in Galileo's experiment to calculate the acceleration due to gravity and has been used by students for centuries to explore the laws of motion.  Here we will examine a block sliding down a frictionless inclined plane as shown below.  The y axis is perpendicular to the incline and  the x axis is parallel to incline.

\begin{figure}
\includegraphics[scale=.85]{InclinePlane.eps}
\vspace{20 pt}
\caption{ Inclined Plane}
\label{Figure 1}
\end{figure}


The first thing to do is draw a free body diagram to describe the external forces acting on our object and the coordinate system for the problem.

\begin{figure}
\includegraphics[scale=.85]{FreeBodyDiagram.eps}
\vspace{20 pt}
\caption{Free Body Diagram}
\label{Figure 2}
\end{figure}

Applying Newton's 2nd law to both x and y

$$ \sum \vec{F} = m \vec{a} $$

{\bf y-dir} \\

First note that the block is stationary in the y direction, so we know that the acceleration is zero.

$$ \sum F_y = 0 $$

The two forces in the y direction are due to the normal force applied by the incline and the force due to gravity.

$$ \sum F_y = N - mg \cos \theta = 0 $$

{\bf x-dir} \\

With the block sliding down the frictionless incline, we get

$$ \sum F_x = mg \sin \theta = m a_x $$

There are several quantities of interest, but let us start with the basics of acceleration, velocity and displacement.  For acceleration we see that it is constant in the x direction

$$ a_x = mg \sin \theta $$

Next, let us calculate the velocity at a given displacement.</content>
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