<?xml version="1.0" encoding="UTF-8"?>

<record version="1" id="240">
 <title>application of Gauss' law, a cat's meow</title>
 <name>ACatsMeowApplicationOfGaussLaw</name>
 <created>2006-12-18 23:14:26</created>
 <modified>2006-12-18 23:14:26</modified>
 <type>Example</type>
<parent id="238">Gauss's Law</parent>
 <creator id="1" name="bloftin"/>
 <modifier id="1" name="bloftin"/>
 <author id="1" name="bloftin"/>
 <classification>
	<category scheme="msc" code="40-XX"/>
	<category scheme="msc" code="41.20.Cv"/>
 </classification>
 <keywords>
	<term>Gauss</term>
 </keywords>
 <preamble>% this is the default PlanetMath preamble.  as your knowledge
% of TeX increases, you will probably want to edit this, but
% it should be fine as is for beginners.

% almost certainly you want these
\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}

% used for TeXing text within eps files
%\usepackage{psfrag}
% need this for including graphics (\includegraphics)
\usepackage{graphicx}
% for neatly defining theorems and propositions
%\usepackage{amsthm}
% making logically defined graphics
%\usepackage{xypic}

% there are many more packages, add them here as you need them

% define commands here</preamble>
 <content>If you know the amount of charge contained within a Gaussian surface, then the total flux of the electric field generated by the enclosed charge is calculated from Gauss' law.

As a demonstration, imagine a pair of cats that have charges placed on them by their loyal masters.  Although the contours of the cats' elegant frames represent a complicated geometry, calculating the flux is a simple task if the charge on the cats is known.  The flux through the Gaussian surface in Figure 1 is given by Gauss' law

\begin{equation}
\Phi = \frac{q_1 + q_2}{\epsilon_0}
\end{equation}


\vspace{10 pt}

\begin{center}
\includegraphics[scale=.6]{Cats.eps}

{\bf Figure 1:} Gaussian Surface Encompassing Two Cats
\end{center}

Note that we add the charges in equation (1) because it is the net enclosed charge.  For exampke if the charge on cat 1 is $10.5  \,\, [\mu C]$ and the charge on the cat 2 is $12.2 [\mu C]$, then the total flux through $G$ is

$$\Phi = \frac{10.5\times 10^{-8} \, [C] + 12.2\times 10^{-8} \, [C] }{8.85 \times 10^{-12} \, [C^2/N m^2]}$$
$$ \Phi = 3073.4 \,\, [N m^2/C]$$


The reverse of this problem is another important result.  If we measure the flux through a given Gaussian surface, then we can calculate the amount of enclosed charge.

\begin{thebibliography}{9}

\bibitem{Figure1}  Figure 1, The Cat Clip art is public domain and was downloaded from \PMlinkexternal{WP Clipart}{ http://www.wpclipart.com/}

\end{thebibliography}</content>
</record>
