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<record version="1" id="282">
 <title>test</title>
 <name>Test</name>
 <created>2008-07-11 03:58:41</created>
 <modified>2008-07-11 03:58:41</modified>
 <type>Definition</type>
 <creator id="1" name="bloftin"/>
 <modifier id="1" name="bloftin"/>
 <author id="1" name="bloftin"/>
 <classification>
	<category scheme="msc" code="00-XX"/>
 </classification>
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 <content>\noindent
abbreviation According again all all all all Alltogether, also always and and and and and applied are arguments as at at at

\noindent
be belong

\noindent
$\vee\ulcorner \mathrm{o}\mathrm{n}\mathrm{d}\mathrm{i}\mathrm{t}\mathrm{i}\mathrm{o}\mathrm{n}$ consider

\noindent
Diederich

\noindent
a enough E. ex- expression

\noindent
Oollowing following, For for for for for for for for Fornaess functions get get get gives gives:

\noindent
Save have hold

\noindent
tf In in in in inequality instead is It it

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1.

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K.

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Leviform Leviform

\noindent
must

\noindent
$(\hat{\xi},\hat{\eta})\in \mathbb{C}^{2}\rho=-\delta(2-\delta).\hat{h}\in C^{2}(\overline{\Omega}_{r}), (\hat{\xi},\hat{\eta})\in \mathbb{C}^{2}, (\hat{\xi},\hat{\eta})\in \mathbb{C}^{2}.\ \displaystyle \mathcal{L}_{\sigma}(p;(\xi,\ \eta))\frac{\partial^{2}\rho}{\partial w\partial\overline{w}}=1;\zeta_{=}\exp(i\ln|z|^{2}) \delta=0, p=(z,\ 0)\in M_{r}.\ \displaystyle \frac{\partial^{2}\rho}{\partial zk}=2\frac{\delta}{|z|^{2}}$;

\noindent
$|p\sigma\sigma\sigma\sigma z\Omega_{r}\hat{\sigma}.\ \Omega_{r}$ : $\Omega_{r}.$) $0&lt;\delta&lt;1(\xi,\ \eta)0&lt;\delta&lt;1.1\leqq|z|\leqq r1\leqq|z|\leqq r1\leqq|z|\leqq r$

\noindent
$\mathrm{z}\in \mathbb{C}, \displaystyle \delta\in \mathrm{R}\frac{\partial\rho}{\partial z}=0;(\hat{\xi},\ \delta\hat{\eta})(\xi,\ \eta)\in \mathbb{C}^{2}$

\noindent
$p=(z,\ -\delta\exp(i\ln|z|^{2}))].\ \displaystyle \frac{\partial\rho}{\partial w}=(1-\delta)\exp(i\ln|z|^{2});\frac{\partial^{2}\rho}{\partial z\partial\overline{w}}=\frac{i}{Z}\exp(i\ln|z|^{2})$;

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$[)=(z,\ w)=(z,\ -\delta\exp(i\ln|z|^{2}))$

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$+\displaystyle \tau\delta\hat{h}+\tau(1-\tau)\frac{(1-\delta)^{2}}{2-\delta}\hat{h})|\eta|^{2}\}.\hat{\sigma}(z,\ w)=-\tilde{h}(|z|^{2},\ w)(-\rho_{r}(z,\ w))^{1/\iota}$

\noindent
$+(2-\displaystyle \delta)(-\delta^{2}(2-\delta)\frac{\partial^{2}\hat{h}}{\partial w\partial\overline{w}}+2\tau\delta(1-\delta){\rm Re}(\zeta\frac{\partial\hat{h}}{\partial w})$

\noindent
$+2\displaystyle \delta(2-\delta){\rm Re}[(-\delta(2-\delta)\frac{\partial^{2}\hat{h}}{\partial z\partial\overline{w}}+\tau(1-\delta)\frac{\partial\hat{h}}{\partial z}+\tau\frac{i}{Z}\zeta\hat{h})\xi\not\in$

\noindent
$g_{\sigma}(p;(\displaystyle \xi,\ \eta))=\delta^{\tau-2}(2-\delta)^{\tau-2}\{\delta^{2}(2-\delta)(-(2-\delta)\frac{\partial h}{\partial z\partial\overline{z}}+2\tau\hat{h}\frac{1}{|z|^{2}})|\xi|^{2}$

\noindent
$+(-\displaystyle \delta^{2}(2-\delta)\frac{\partial^{2}\hat{h}}{\partial w\partial\overline{w}}+2\tau\delta(1-\delta){\rm Re}(\zeta\frac{\partial\hat{h}}{\partial w})+\tau\delta\hat{h}+\tau(1-\tau)\frac{(1-\delta)^{2}}{2-\delta}\hat{h})|\hat{\eta}|^{2}\geqq 0$

\noindent
$(^{-2\frac{\partial^{2}\hat{h}}{\partial z\partial\overline{z}}+2\frac{\tau}{|z|^{2}}\hat{h})|\xi|^{2}+2{\rm Re}}([\displaystyle \tau\zeta(\frac{\partial\hat{h}}{\partial z}+\frac{i}{Z}\hat{h})\hat{\xi}\hat{\eta}]+\frac{1}{2}\tau(1-\tau)\hat{h}|\hat{\eta}|^{2}\geqq 0$

\noindent
$(^{-(2-\delta)\frac{\partial^{2}\hat{h}}{\partial z\mathit{5}\overline{z}}+2\frac{\tau}{|z|^{2}}\hat{h})|\xi|^{2}+2{\rm Re}}([(-\displaystyle \delta(2-\delta)\frac{\partial^{2}\hat{h}}{\partial w\partial\overline{w}}+\tau(1-\delta)\frac{\partial\hat{h}}{\partial z}+\tau\frac{i}{Z}\zeta\hat{h})\hat{\xi}\hat{\eta}$

\noindent
[lecessary

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obviously, of of of on on out

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286 [ (15) (17) (17) (18 (19) (They, )

\noindent
plurisubharmonic points points points: pression proof

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$\mathrm{r}$

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finc suppose

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that that the the the the the the the the the the the the then these This This this this to to to to to turn

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vecto vector

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we we we we we we we will will with with with with with write written</content>
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