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<record version="1" id="283">
 <title>transformation from rectangular to generalized coordinates</title>
 <name>TransformationFromRectangularToGeneralizedCoordinates</name>
 <created>2008-07-15 10:48:33</created>
 <modified>2008-07-15 10:48:33</modified>
 <type>Topic</type>
 <creator id="1" name="bloftin"/>
 <modifier id="1" name="bloftin"/>
 <author id="1" name="bloftin"/>
 <classification>
	<category scheme="msc" code="45.20.Jj"/>
 </classification>
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 <content>We take a system with a total of $3N \equiv n$ Cartesian coordinates of 
which $\nu$ are independent.  We denote Cartesian coordinates 
by the same letter $x_i$, understanding by this symbol all the coordinates $x, y, z$; this means that $i$ varies from $1$ to $3N$, that is, from $1$ to $n$.  The generalized coordinates we denote by $q_\alpha$ $(l \le \alpha \le \nu )$. Since the generalized coordinates completely specify the position of their system, $x_i$ are their unique functions: 

$$x_i = x_i (q_1, q_2,\dots q_\alpha,\dots,q_v)$$ 

From this it is easy to obtain an expression for the Cartesian components of velocity. Differentiating the function of many variables 
$x_i(\dots q_\alpha)$ with respect to time, we have 

\begin{equation}
\frac{ dx_i}{dt} = \sum_{\alpha=1}^{\nu} \frac{\partial x_i}{\partial q_\alpha} \frac{d q_\alpha}{dt}
\end{equation}

In the subsequent derivation we shall often have to perform 
summations with respect to all the generalized coordinates $q_\alpha$, and double and triple sums will be encountered.  In order to save space we will use Einstein summation. 

The total derivative with respect to time is usually denoted by a dot over the corresponding variable:

$$ \frac{d x_i}{dt} = \dot{x_i}; \,\,\, \frac{d q_\alpha}{dt} = \dot{q_\alpha} $$

In this notation, the velocity (1) in abbreviated form becomes:

\begin{equation} \dot{x_i} = \frac{\partial x_i}{\partial q_\alpha} \dot{q_\alpha}
\end{equation}

Differentiating this with respect to time again, we obtain an expression for the Cartesian components of acceleration:

$$\ddot{x_i}= \frac{d}{dt}\left( \frac{\partial x_i}{\partial q_\alpha} \right ) \dot{q_\alpha} + \frac{\partial x_i}{\partial q_\alpha} \ddot{q_\alpha} $$

The total derivative in the first term is written as usual:

$$ \frac{d}{dt}\left( \frac{\partial x_i}{\partial q_\alpha} \right ) = \frac{\partial^2 x_i}{\partial q_\beta \partial q_\alpha} \dot{q_\beta} $$

The Greek symbol over which the summatino is performed is deonted by the letter $\beta$ to avoid confusion with the symbol $\alpha$, which denotes the summation in the expression for velocity (2).  Thus we obtain the desired expression for $\ddot{x_i}$:

\begin{equation}
\ddot{x_i} = \frac{\partial^2 x_i}{\partial q_\beta \partial q_\alpha} \dot{q_\beta} \dot{q_\alpha} + \frac{\partial x_i}{\partial q_\alpha} \ddot{q_\alpha}
\end{equation}

The first term on the right-hand side contains a double summation with respect to $\alpha$ and $\beta$.</content>
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